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Application of Integration question

2021 · Shift 2 · Q29
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  5. /2021 · Shift 2 · Q29

Application of Integration question

2021 · Shift 2 · Q29

JEE AdvancedMathematicsApplication of IntegrationNumerical+2 / −1
Let f1 : (0, ∞\infty∞) →\to→ R and f2 : (0, ∞\infty∞) →\to→ R be defined by f1(x)=∫0x∏j=121(t−j)jdt{f_1}(x) = \int\limits_0^x {\prod\limits_{j = 1}^{21} {{{(t - j)}^j}dt} }f1​(x)=0∫x​j=1∏21​(t−j)jdt, x > 0 and f2(x)=98(x−1)50−600(x−1)49+2450,x>0{f_2}(x) = 98{(x - 1)^{50}} - 600{(x - 1)^{49}} + 2450,x \gt 0f2​(x)=98(x−1)50−600(x−1)49+2450,x>0, where, for any positive integer n and real numbers a1, a2, ....., an, ∏olimitsi=1nai\prod olimits_{i = 1}^n {{a_i}}∏olimitsi=1n​ai​ denotes the product of a1, a2, ....., an. Let mi and ni, respectively, denote the number of points of local minima and the number of points of local maxima of function fi, i = 1, 2 in the interval (0, ∞\infty∞). The value of 6m2+4n2+8m2n26{m_2} + 4{n_2} + 8{m_2}{n_2}6m2​+4n2​+8m2​n2​ is ‾\underline{\hspace{2cm}}​.
Numerical answer
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