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Application of Derivatives question

2014 · Shift 1 · Q27
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  5. /2014 · Shift 1 · Q27

Application of Derivatives question

2014 · Shift 1 · Q27

JEE AdvancedMathematicsApplication of DerivativesNumerical+3 / −1
The slope of the tangent to the curve (y−x5)2=x(1+x2)2{\left( {y - {x^5}} \right)^2} = x{\left( {1 + {x^2}} \right)^2}(y−x5)2=x(1+x2)2 at the point (1,3)(1, 3)(1,3) is
Numerical answer
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