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Application of Derivatives question

2007 · Shift 1 · Q24
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  5. /2007 · Shift 1 · Q24

Application of Derivatives question

2007 · Shift 1 · Q24

JEE AdvancedMathematicsApplication of DerivativesMCQ+3 / −1
Let f(x)f(x)f(x) be differentiable on the interval (0, ∞\infty∞) such that f(1)=1f(1)=1f(1)=1, and lim⁡t→xt2f(x)−x2f(t)t−x=1\mathop {\lim }\limits_{t \to x} {{{t^2}f(x) - {x^2}f(t)} \over {t - x}} = 1t→xlim​t−xt2f(x)−x2f(t)​=1 for each x>0x \gt 0x>0. Then f(x)f(x)f(x) is
  1. A
    13x+2x23{1 \over {3x}} + {{2{x^2}} \over 3}3x1​+32x2​
  2. B
    −13x+4x23- {1 \over {3x}} + {{4{x^2}} \over 3}−3x1​+34x2​
  3. C
    −1x+2x2- {1 \over x} + {2 \over {{x^2}}}−x1​+x22​
  4. D
    1x{1 \over x}x1​
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