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3D Geometry question

2018 · Shift 2 · Q31
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  5. /2018 · Shift 2 · Q31

3D Geometry question

2018 · Shift 2 · Q31

JEE AdvancedMathematics3D GeometryNumerical+3 / −1
Consider the cube in the first octant with sides OP, OQ and OR of length 1, along the X-axis, Y-axis and Z-axis, respectively, where O(0, 0, 0) is the origin. Let S(12,12,12)S\left( {{1 \over 2},{1 \over 2},{1 \over 2}} \right)S(21​,21​,21​) be the centre of the cube and T be the vertex of the cube opposite to the origin O such that S lies on the diagonal OT. If p = SP, q = SQ, r = SR and t = ST, then the value of |(p ×\times× q) ×\times×(r ×\times× t)| is ............
Numerical answer
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