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3D Geometry question

2013 · Shift 1 · Q28

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PYQ Library
JEE Advanced
Mathematics
3D Geometry
2013 · Shift 1 · Q28

3D Geometry question

2013 · Shift 1 · Q28

JEE AdvancedMathematics3D GeometryMCQ+3 / −1

Perpendiculars are drawn from points on the line

\frac{x+2}{2}=\frac{y+1}{-1}=\frac{z}{3}

to the plane

x+y+z=3

. The foot of perpendiculars lie on the line

A
$\frac{x}{5}=\frac{y-1}{8}=\frac{z-2}{-13}$
B
$\frac{x}{2}=\frac{y-1}{3}=\frac{z-2}{-5}$
C
$\frac{x}{4}=\frac{y-1}{3}=\frac{z-2}{-7}$
D
$\frac{x}{2}=\frac{y-1}{-7}=\frac{z-2}{5}$

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