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3D Geometry question

2013 · Shift 2 · Q23
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  2. /JEE Advanced
  3. /Mathematics
  4. /3D Geometry
  5. /2013 · Shift 2 · Q23

3D Geometry question

2013 · Shift 2 · Q23

JEE AdvancedMathematics3D GeometryMCQ+4 / −1
Consider the lines L1:x−12=y−1=z+31,L2:x−41=y+31=z+32{L_1}:{{x - 1} \over 2} = {y \over { - 1}} = {{z + 3} \over 1},{L_2} : {{x - 4} \over 1} = {{y + 3} \over 1} = {{z + 3} \over 2}L1​:2x−1​=−1y​=1z+3​,L2​:1x−4​=1y+3​=2z+3​ and the planes P1:7x+y+2z=3,P2=3x+5y−6z=4.{P_1}:7x + y + 2z = 3,{P_2} = 3x + 5y - 6z = 4.P1​:7x+y+2z=3,P2​=3x+5y−6z=4. Let ax+by+cz=dax+by+cz=dax+by+cz=d be the equation of the plane passing through the point of intersection of lines L1{L_1}L1​ and L2,{L_2},L2​, and perpendicular to planes P1{P_1}P1​ and P2.{P_2}.P2​. Match List III with List IIIIII and select the correct answer using the code given below the lists: List III(P.) a=a=a=(Q.) b=b=b=(R.) c=c=c=(S.) d=d=d= List IIIIII(1.) 131313(2.) −3-3−3(3.) 111(4.) −2-2−2
  1. A
    P=3,Q=2,R=4,S=1P = 3,Q = 2,R = 4,S = 1P=3,Q=2,R=4,S=1
  2. B
    P=1,Q=3,R=4,S=2P = 1,Q = 3,R = 4,S = 2P=1,Q=3,R=4,S=2
  3. C
    P=3,Q=2,R=1,S=4P = 3,Q = 2,R = 1,S = 4P=3,Q=2,R=1,S=4
  4. D
    P=2,Q=4,R=1,S=3P = 2,Q = 4,R = 1,S = 3P=2,Q=4,R=1,S=3
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