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3D Geometry question

2010 · Shift 1 · Q41

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PYQ Library
JEE Advanced
Mathematics
3D Geometry
2010 · Shift 1 · Q41

3D Geometry question

2010 · Shift 1 · Q41

JEE AdvancedMathematics3D GeometryNumerical+4 / −1

If the distance between the plane

Ax-2y+z=d

and the plane containing the lines

{{x - 1} \over 2} = {{y - 2} \over 3} = {{z - 3} \over 4}

and

{{x - 2} \over 3} = {{y - 3} \over 4} = {{z - 4} \over 5}\,

is

\sqrt 6 \,\,,

then

\left| d \right|

is

\underline{\hspace{2cm}}

.

Numerical answer

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