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3D Geometry question

2012 · Shift 2 · Q22
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  2. /JEE Advanced
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  5. /2012 · Shift 2 · Q22

3D Geometry question

2012 · Shift 2 · Q22

JEE AdvancedMathematics3D GeometryMultiple correct+4 / −1
If the straight lines  x−12=y+1k=z2\,{{x - 1} \over 2} = {{y + 1} \over k} = {z \over 2}2x−1​=ky+1​=2z​ and x+15=y+12=zk{{x + 1} \over 5} = {{y + 1} \over 2} = {z \over k}5x+1​=2y+1​=kz​ are coplanar, then the plane (s) containing these two lines is (are)
  1. A
    y+2z=−1y+2z=-1y+2z=−1
  2. B
    y+z=−1y+z=-1y+z=−1
  3. C
    y−z=−1y-z=-1y−z=−1
  4. D
    y−2z=−1y-2z=-1y−2z=−1
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