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3D Geometry question

2010 · Shift 2 · Q23
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  2. /JEE Advanced
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  5. /2010 · Shift 2 · Q23

3D Geometry question

2010 · Shift 2 · Q23

JEE AdvancedMathematics3D GeometryMCQ+4 / −1
If the distance of the point P(1,−2,1)P(1, -2, 1)P(1,−2,1) from the plane x+2y−2z =α,x+2y-2z\, = \alpha ,x+2y−2z=α, where α>0,\alpha \gt 0,α>0, is 5,5,5, then the foot of the perpendicular from PPP to the planes is
  1. A
    (83,43,−73)\left( {{8 \over 3},{4 \over 3}, - {7 \over 3}} \right)(38​,34​,−37​)
  2. B
    (43,−43,13)\left( {{4 \over 3},-{4 \over 3}, {1 \over 3}} \right)(34​,−34​,31​)
  3. C
    (13,23,103)\left( {{1 \over 3},{2 \over 3}, {10 \over 3}} \right)(31​,32​,310​)
  4. D
    (23,−13,53)\left( {{2 \over 3},-{1 \over 3}, {5 \over 3}} \right)(32​,−31​,35​)
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