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P Block Elements question

2024 · Shift 2 · Q4
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P Block Elements question

2024 · Shift 2 · Q4

JEE AdvancedChemistryP Block ElementsMCQ+3 / −1
The species formed on fluorination of phosphorus pentachloride in a polar organic solvent are
  1. A
    [PF4]+[PF6]−\left[\mathrm{PF}_4\right]^{+}\left[\mathrm{PF}_6\right]^{-}[PF4​]+[PF6​]− and [PCl4]+[PF6]−\left[\mathrm{PCl}_4\right]^{+}\left[\mathrm{PF}_6\right]^{-}[PCl4​]+[PF6​]−
  2. B
    [PCl4]+[PCl4 F2]−\left[\mathrm{PCl}_4\right]^{+}\left[\mathrm{PCl}_4 \mathrm{~F}_2\right]^{-}[PCl4​]+[PCl4​ F2​]− and [PCl4]+[PF6]−\left[\mathrm{PCl}_4\right]^{+}\left[\mathrm{PF}_6\right]^{-}[PCl4​]+[PF6​]−
  3. C
    PF3\mathrm{PF}_3PF3​ and PCl3\mathrm{PCl}_3PCl3​
  4. D
    PF5\mathrm{PF}_5PF5​ and PCl3\mathrm{PCl}_3PCl3​
View written solutionFree

Correct answer: B

  1. Identify the reaction type

    We are asked about the species formed on fluorination of PCl5\mathrm{PCl_5}PCl5​ in a polar organic solvent.

    In polar solvents, phosphorus pentachloride behaves as an ionic species: PCl5⇌[PCl4]+[PCl6]−\mathrm{PCl_5 \rightleftharpoons [PCl_4]^+ [PCl_6]^-}PCl5​⇌[PCl4​]+[PCl6​]−

    On fluorination, fluorine substitutes chloride stepwise, and mixed halo-phosphorus ionic species are formed.

  2. Known behavior of fluorination of PCl5\mathrm{PCl_5}PCl5​

    Fluorination of PCl5\mathrm{PCl_5}PCl5​ does not directly give only simple molecular products like PF5\mathrm{PF_5}PF5​ or PF3\mathrm{PF_3}PF3​ in polar organic medium.

    Instead, due to ionic dissociation in such solvents, species such as: [PCl4]+[PCl4F2]−[\mathrm{PCl_4}]^+[\mathrm{PCl_4F_2}]^-[PCl4​]+[PCl4​F2​]− and [PCl4]+[PF6]−[\mathrm{PCl_4}]^+[\mathrm{PF_6}]^-[PCl4​]+[PF6​]− are formed.

  3. Check each option

    Option A: [PF4]+[PF6]−[\mathrm{PF_4}]^+[\mathrm{PF_6}]^-[PF4​]+[PF6​]− and [PCl4]+[PF6]−[\mathrm{PCl_4}]^+[\mathrm{PF_6}]^-[PCl4​]+[PF6​]−

    • [PCl4]+[PF6]−[\mathrm{PCl_4}]^+[\mathrm{PF_6}]^-[PCl4​]+[PF6​]− is known.
    • But [PF4]+[PF6]−[\mathrm{PF_4}]^+[\mathrm{PF_6}]^-[PF4​]+[PF6​]− is not the characteristic species formed in this fluorination of PCl5\mathrm{PCl_5}PCl5​ in polar organic solvent.
    • So this option is incorrect.

    Option B: [PCl4]+[PCl4F2]−[\mathrm{PCl_4}]^+[\mathrm{PCl_4F_2}]^-[PCl4​]+[PCl4​F2​]− and [PCl4]+[PF6]−[\mathrm{PCl_4}]^+[\mathrm{PF_6}]^-[PCl4​]+[PF6​]−

    • These are the standard ionic fluorination products observed in polar organic solvent.
    • Hence correct.

    Option C: PF3\mathrm{PF_3}PF3​ and PCl3\mathrm{PCl_3}PCl3​

    • These would imply reduction/disproportionation products, not the expected fluorination products here.
    • Incorrect.

    Option D: PF5\mathrm{PF_5}PF5​ and PCl3\mathrm{PCl_3}PCl3​

    • This is also not the correct description for fluorination in polar organic medium, where ionic species are stabilized.
    • Incorrect.
  4. Final conclusion

    The correct species formed are: [PCl4]+[PCl4F2]−and[PCl4]+[PF6]−[\mathrm{PCl_4}]^+[\mathrm{PCl_4F_2}]^- \quad \text{and} \quad [\mathrm{PCl_4}]^+[\mathrm{PF_6}]^-[PCl4​]+[PCl4​F2​]−and[PCl4​]+[PF6​]−

    Therefore, the correct option is B.

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