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Electrochemistry question

2025 · Shift 2 · Q14

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JEE Advanced
Chemistry
Electrochemistry
2025 · Shift 2 · Q14

Electrochemistry question

2025 · Shift 2 · Q14

JEE AdvancedChemistryElectrochemistryNumerical+4 / −1

An electrochemical cell is fueled by the combustion of butane at 1 bar and 298 K . Its cell potential is

\frac{\boldsymbol{X}}{F} \times 10^3

volts, where

F

is the Faraday constant. The value of

\boldsymbol{X}

is

\underline{\hspace{2cm}}

. Use: Standard Gibbs energies of formation at 298 K are:

\Delta_f G_{\mathrm{CO}_2}^o=-394 \mathrm{~kJ} \mathrm{~mol}^{-1} ; \Delta_f G_{\text {water }}^o=-237 \mathrm{~kJ} \mathrm{~mol}^{-1} ; \Delta_f G_{\text {butane }}^o=-18 \mathrm{~kJ} \mathrm{~mol}^{-1}

Numerical answer

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