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Electrochemistry question

2022 · Shift 2 · Q3
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Electrochemistry question

2022 · Shift 2 · Q3

JEE AdvancedChemistryElectrochemistryNumerical+3 / −1
Consider the strong electrolytes ZmXn,UmYpZ_{m} X_{n}, U_{m} Y_{p}Zm​Xn​,Um​Yp​ and VmXnV_{m} X_{n}Vm​Xn​. Limiting molar conductivity ( Λ0\Lambda^{0}Λ0) of UmYp\mathrm{U}_{\mathrm{m}} \mathrm{Y}_{\mathrm{p}}Um​Yp​ and VmXn\mathrm{V}_{\mathrm{m}} \mathrm{X}_{\mathrm{n}}Vm​Xn​ are 250 and 440 S cm2 mol−1440 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}440 S cm2 mol−1, respectively. The value of (m+n+p)(\mathrm{m}+\mathrm{n}+\mathrm{p})(m+n+p) is

Given:

Ion Zn+\mathrm{Z}^{\mathrm{n}+}Zn+ Up+\mathrm{U}^{\mathrm{p}+}Up+ Vn+\mathrm{V}^{\mathrm{n}+}Vn+ Xm−\mathrm{X}^{\mathrm{m}-}Xm− Ym−\mathrm{Y}^{\mathrm{m}-}Ym−
λ0( S cm2 mol−1)\lambda^{0}\left(\mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}\right)λ0( S cm2 mol−1) 50.050.050.0 25.025.025.0 100.0100.0100.0 80.080.080.0 100.0100.0100.0

λ0\lambda^{0}λ0 is the limiting molar conductivity of ions

The plot of molar conductivity (Λ\LambdaΛ) of ZmXnvs c1/2\mathrm{Z}_{\mathrm{m}} \mathrm{X}_{\mathrm{n}} v s\, \mathrm{c}^{1 / 2}Zm​Xn​vsc1/2 is given below.

JEE Advanced 2022 Paper 2 Online Chemistry - Electrochemistry Question 11 English
Numerical answer
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