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Electrochemistry question

2021 · Shift 2 · Q4
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Electrochemistry question

2021 · Shift 2 · Q4

JEE AdvancedChemistryElectrochemistryMultiple correct+4 / −2
Some standard electrode potentials at 298 K are given below : Pb2+Pb^{2+}Pb2+ /PbPbPb = −-− 0.13 V Ni2+Ni^{2+}Ni2+ /NiNiNi = −-− 0.24 V Cd2+Cd^{2+}Cd2+ /CdCdCd =−-− 0.40 V Fe2+Fe^{2+}Fe2+ /FeFeFe =−-− 0.44 V To a solution containing 0.001 M of X2+X^{2+}X2+ and 0.1 M of Y2+Y^{2+}Y2+, the metal rods X and Y are inserted (at 298 K) and connected by a conducting wire. This resulted in dissolution of X. The correct combination(s) of X and Y, respectively, is(are) (Given : Gas constant, R = 8.314 J K −-− mol −-− 1, Faraday constant, F = 96500 C mol −-− 1)
  1. A
    Cd and Ni
  2. B
    Cd and Fe
  3. C
    Ni and Pb
  4. D
    Ni and Fe
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