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Electrochemistry question

2020 · Shift 1 · Q15
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Electrochemistry question

2020 · Shift 1 · Q15

JEE AdvancedChemistryElectrochemistryNumerical+4 / −1
Consider a 70% efficient hydrogen-oxygen fuel cell working under standard conditions at 1 bar and 298 K. Its cell reaction is H2(g)+12O2(g)→H2O(l){H_2}(g) + {1 \over 2}{O_2}(g)\xrightarrow{} {H_2}O(l)H2​(g)+21​O2​(g)​H2​O(l) The work derived from the cell on the consumption of 1.0 ×\times× 10 −-− 3 mole of H2H_2H2​(g) is used to compress 1.00 mole of a monoatomic ideal gas in a thermally insulated container. What is the change in the temperature (in K) of the ideal gas? The standard reduction potentials for the two half-cells are given below : O2(g)+4H+(aq)+4e−→2H2O(l),{O_2}(g) + 4{H^ + }(aq) + 4{e^ - }\xrightarrow{} 2{H_2}O(l),O2​(g)+4H+(aq)+4e−​2H2​O(l), Eo=1.23V2H+(aq)+2e−→H2(g),Eo=0.00 V{E^o} = 1.23V2{H^ + }(aq) + 2{e^ - }\xrightarrow{} {H_2}(g),{E^o} = 0.00\,VEo=1.23V2H+(aq)+2e−​H2​(g),Eo=0.00V Use, F=96500 C mol−1F = 96500\,C\,mo{l^{ - 1}}F=96500Cmol−1, R=8.314 J mol−1 K−1R = 8.314\,J\,mo{l^{ - 1}}\,{K^{ - 1}}R=8.314Jmol−1K−1.
Numerical answer
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