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Coordination Compounds question

2024 · Shift 1 · Q11
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Coordination Compounds question

2024 · Shift 1 · Q11

JEE AdvancedChemistryCoordination CompoundsNumerical+4 / −1
Among V(CO)6,Cr(CO)5,Cu(CO)3,Mn(CO)5,Fe(CO)5,[Co(CO)3]3−,[Cr(CO)4]4−\mathrm{V}(\mathrm{CO})_6, \mathrm{Cr}(\mathrm{CO})_5, \mathrm{Cu}(\mathrm{CO})_3, \mathrm{Mn}(\mathrm{CO})_5, \mathrm{Fe}(\mathrm{CO})_5,\left[\mathrm{Co}(\mathrm{CO})_3\right]^{3-},\left[\mathrm{Cr}(\mathrm{CO})_4\right]^{4-}V(CO)6​,Cr(CO)5​,Cu(CO)3​,Mn(CO)5​,Fe(CO)5​,[Co(CO)3​]3−,[Cr(CO)4​]4−, and Ir⁡(CO)3\operatorname{Ir}(\mathrm{CO})_3Ir(CO)3​, the total number of species isoelectronic with Ni(CO)4\mathrm{Ni}(\mathrm{CO})_4Ni(CO)4​ is ‾\underline{\hspace{2cm}}​. [Given, atomic number: V=23,Cr=24,Mn=25,Fe=26,Co=27,Ni=28,Cu=29,Ir=77\mathrm{V}=23, \mathrm{Cr}=24, \mathrm{Mn}=25, \mathrm{Fe}=26, \mathrm{Co}=27, \mathrm{Ni}=28, \mathrm{Cu}=29, \mathrm{Ir}=77V=23,Cr=24,Mn=25,Fe=26,Co=27,Ni=28,Cu=29,Ir=77 ]
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