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Coordination Compounds question

2020 · Shift 2 · Q7
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Coordination Compounds question

2020 · Shift 2 · Q7

JEE AdvancedChemistryCoordination CompoundsMultiple correct+4 / −2
In an experiment, m grams of a compound X (gas/liquid/solid) taken in a container is loaded in a balance as shown in figure I below. In the presence of a magnetic field, the pan with X is either deflected upwards (figure II), or deflected downwards (figure III), depending on the compound X. Identify the correct statement(s). JEE Advanced 2020 Paper 2 Offline Chemistry - Coordination Compounds Question 38 English
  1. A
    If X is H2OH_2OH2​O(l), deflection of the pan is upwards
  2. B
    If X is K4[Fe(CN)6]K_4[Fe(CN)_6]K4​[Fe(CN)6​](s), deflection of the pan is upwards.
  3. C
    If X is O2O_2O2​(g), deflection of the pan is downwards.
  4. D
    If X is C6H6C_6H_6C6​H6​(l), deflection of the pan is downwards
View written solutionFree

Correct answer: D

  1. Principle involved

When a substance is placed in a non-uniform magnetic field:

  • Paramagnetic substances are attracted toward the stronger magnetic field.
  • Diamagnetic substances are repelled from the stronger magnetic field.

From the figure description, the magnet is placed above the pan. Therefore:

  • If the substance is attracted upward toward the magnet, the pan moves upwards.
  • If the substance is repelled downward away from the magnet, the pan moves downwards.

So:

  • Paramagnetic ⇒\Rightarrow⇒ pan deflects upwards
  • Diamagnetic ⇒\Rightarrow⇒ pan deflects downwards

  1. Check each option

Option A: H2O(l)H_2O(l)H2​O(l)

Water is diamagnetic because all electrons are paired.

Hence it is repelled by the magnetic field, so the pan should move downwards, not upwards.

Therefore, A is false.


Option B: K4[Fe(CN)6](s)K_4[Fe(CN)_6](s)K4​[Fe(CN)6​](s)

In [Fe(CN)6]4−[Fe(CN)_6]^{4-}[Fe(CN)6​]4−:

  • Oxidation state of Fe: x+6(−1)=−4⇒x=+2x + 6(-1) = -4 \Rightarrow x=+2x+6(−1)=−4⇒x=+2
  • So Fe is Fe2+Fe^{2+}Fe2+, i.e. 3d63d^63d6.
  • CN−CN^-CN− is a strong field ligand, so the complex is low spin: t2g6eg0t_{2g}^6 e_g^0t2g6​eg0​

All electrons are paired, so the complex is diamagnetic.

Hence the pan should move downwards, not upwards.

Therefore, B is false.


Option C: O2(g)O_2(g)O2​(g)

Molecular oxygen has two unpaired electrons in antibonding π∗\pi^*π∗ orbitals, so it is paramagnetic.

Therefore it is attracted toward the magnetic field and the pan moves upwards, not downwards.

Therefore, C is false.


Option D: C6H6(l)C_6H_6(l)C6​H6​(l)

Benzene has all electrons paired, so it is diamagnetic.

Hence it is repelled from the magnetic field and the pan moves downwards.

Therefore, D is true.


  1. Final derived answer

The correct option is:

D\boxed{D}D​


  1. Comparison with stored correct answer

Stored correct answer: A,B,CA, B, CA,B,C

My derived answer is DDD only. So I disagree with the stored answer.

The likely issue is that the direction of deflection has been interpreted oppositely in the stored answer. Using the standard rule that a magnet above attracts paramagnetic substances upward and repels diamagnetic substances downward, only benzene gives downward deflection.

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