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Coordination Compounds question

2017 · Shift 1 · Q8
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Coordination Compounds question

2017 · Shift 1 · Q8

JEE AdvancedChemistryCoordination CompoundsNumerical+3 / −1
The sum of the number of lone pairs of electrons on each central atom in the following species is [TeBr6]2−,[BrF2]+,SNF3,{[TeB{r_6}]^{2 - }},{\left[ {Br{F_2}} \right]^ + },SNF_3,[TeBr6​]2−,[BrF2​]+,SNF3​, and [XeF3]−{\left[ {Xe{F_3}} \right]^ - }[XeF3​]−(Atomic numbers: N=7,F=9,S=16,Br=35,Te=52,Xe=54N = 7,F = 9,S = 16,Br = 35,Te = 52,Xe = 54N=7,F=9,S=16,Br=35,Te=52,Xe=54)
Numerical answer
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