- A, , ,
- B, , ,
- C, , ,
- D, , ,
View written solutionFree
Correct answer: A, C
- Principle used
A molecule has a permanent dipole moment if the vector sum of all bond dipoles is non-zero.
So we must check, in each option, whether all four molecules are polar at room temperature.
- Option A: , , ,
-
: bent shape due to lone pair on S. So it is polar.
-
(chlorobenzene): the bond gives a net molecular dipole; molecule is not symmetrically cancelling to zero. Hence polar.
-
: like , it has a bent structure. Therefore bond dipoles do not cancel. Polar.
-
: square pyramidal geometry. This shape is unsymmetrical, so dipoles do not cancel. Polar.
Thus, all four are polar.
✅ Option A is correct.
- Option B: , , ,
-
: linear Equal bond dipoles cancel. Non-polar.
-
: linear, symmetric. Non-polar.
-
: trigonal planar, symmetric. Non-polar.
-
: tetrahedral, unsymmetrical. Polar.
Since not all four are polar, this option is not correct.
❌ Option B is incorrect.
- Option C: , , ,
-
: bent molecule. Hence polar.
-
: trigonal pyramidal due to lone pair on N. Polar.
-
: tetrahedral arrangement around P with one and three bonds; substituents are not identical, so dipoles do not cancel. Polar.
-
: tetrahedral but unsymmetrical because one Cl and three H. Polar.
Thus, all four are polar.
✅ Option C is correct.
- Option D: , , ,
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: trigonal planar and symmetric. Non-polar.
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: bent, polar.
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: octahedral and symmetric. Non-polar.
-
: distorted octahedral / monocapped octahedron, generally polar.
Since and are non-polar, not all four are polar.
❌ Option D is incorrect.
- Final conclusion
The options in which all four molecules possess permanent dipole moment at room temperature are:
- Comparison with stored correct answer
Stored correct answer: A, C
My derived answer: A, C
They match.
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