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Basics of Organic Chemistry question

2019 · Shift 2 · Q14
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Basics of Organic Chemistry question

2019 · Shift 2 · Q14

JEE AdvancedChemistryBasics of Organic ChemistryNumerical+3 / −1
Total number of isomers, considering both structural and stereoisomers of cyclic ethers with the molecular formula C4H8OC_4H_8OC4​H8​O is .................
Numerical answer
View written solutionFree

Correct answer: 10

  1. Molecular formula and degree of unsaturation

For C4H8OC_4H_8OC4​H8​O,

DBE=2C+2−H2=2(4)+2−82=22=1\text{DBE} = \frac{2C+2-H}{2} = \frac{2(4)+2-8}{2} = \frac{2}{2} = 1DBE=22C+2−H​=22(4)+2−8​=22​=1

So there is one degree of unsaturation. Since the compounds asked are cyclic ethers, this one unsaturation is due to one ring.

We must count all cyclic ethers with formula C4H8OC_4H_8OC4​H8​O, including structural isomers + stereoisomers.


  1. Possible cyclic ether ring sizes

Total atoms besides hydrogen are 444 carbons and 111 oxygen. The ring can be:

  • 5-membered ring: 4C+1O4C + 1O4C+1O in ring
  • 4-membered ring: 333 atoms in ring? Actually for a cyclic ether with one O, a 4-membered ring contains 3C+1O3C + 1O3C+1O, leaving one carbon as substituent
  • 3-membered ring: 2C+1O2C + 1O2C+1O, leaving two carbons as substituent(s)

Now enumerate systematically.


  1. Five-membered ring isomer

(i) Tetrahydrofuran

A 5-membered cyclic ether with one oxygen:

tetrahydrofuran\text{tetrahydrofuran}tetrahydrofuran

This has formula C4H8OC_4H_8OC4​H8​O.

Number of isomers here = 1.


  1. Four-membered ring isomers (oxetanes)

Ring = oxetane (3C+1O3C + 1O3C+1O), plus one extra carbon as a methyl substituent.

Because positions adjacent to oxygen are equivalent, there are only two structural possibilities:

(ii) 2-methyloxetane

Substituent on carbon adjacent to O.

This carbon becomes a stereogenic center because it is attached to:

  • CH3CH_3CH3​
  • HHH
  • one side of ring through OOO
  • other side of ring through CH2CH_2CH2​

These four groups are different, so it exists as two enantiomers.

Count = 2.

(iii) 3-methyloxetane

Substituent on carbon opposite to O.

No stereocenter is present here.

Count = 1.

So total from oxetanes =

2+1=32+1=32+1=3

Running total =

1+3=41+3=41+3=4


  1. Three-membered ring isomers (epoxides / oxiranes)

Ring = oxirane (2C+1O2C + 1O2C+1O), and we still need two carbons outside ring.

These two carbons can appear as either:

  • one ethyl substituent on one ring carbon, or
  • two methyl substituents on ring carbon(s)

Now enumerate.

(iv) 2-ethyloxirane

One ethyl substituent on one carbon of oxirane.

That substituted carbon is attached to:

  • C2H5C_2H_5C2​H5​
  • HHH
  • OOO
  • the other ring carbon

Hence it is a stereogenic center. So this gives 2 enantiomers.

Count = 2.

(v) 2,2-dimethyloxirane

Both methyl groups on the same ring carbon.

No stereocenter.

Count = 1.

(vi) 2,3-dimethyloxirane

One methyl on each ring carbon.

This has stereoisomerism:

  • cis-2,3-dimethyloxirane
  • trans-2,3-dimethyloxirane

Now check chirality:

  • The cis form has a plane of symmetry, so it is meso / achiral: 1 isomer.
  • The trans form is chiral and exists as a pair of enantiomers: 2 isomers.

So total for 2,3-dimethyloxirane =

1+2=31+2=31+2=3

Thus total from epoxides =

2+1+3=62+1+3=62+1+3=6

Running total =

4+6=104+6=104+6=10


  1. Final count

Total number of isomers of cyclic ethers with formula C4H8OC_4H_8OC4​H8​O:

1+3+6=101 + 3 + 6 = 101+3+6=10


  1. Comparison with stored answer

Stored correct answer = 10.

Our derived answer = 10.

So the stored answer is correct.

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