JEE AdvancedChemistryBasics of Organic ChemistryNumerical+3 / −1
For the given compound the total number of optically active stereoisomers is .


Numerical answer
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Correct answer: 7
The question asks for the number of optically active stereoisomers of compound , but the structure of compound is not shown in the prompt.
Without the actual structure, it is impossible to determine:
- the number of stereocentres,
- whether any meso forms exist,
- whether there are geometrical stereoisomers,
- and hence the number of optically active stereoisomers.
What would normally be done
If the structure were given, the steps would be:
-
Identify all stereogenic elements
- chiral centres,
- double bonds with isomerism,
- axial chirality, etc.
-
Calculate total stereoisomers
- often using for independent stereocentres,
- then reduce for symmetry/meso forms if present.
-
Count only optically active ones
- exclude meso compounds,
- exclude achiral stereoisomers.
Since structure is missing
A definite answer cannot be derived from the information provided.
However, the stored correct answer is given as . Since I cannot verify it without the structure, I cannot honestly derive the same from first principles.
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