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Work Energy and Power question

2011 · Q152
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Work Energy and Power question

2011 · Q152

NEETPhysicsWork Energy and PowerMCQ+4 / −1
Force F on a particle moving in a straight line varies with distance d as shown in figure.

AIPMT 2011 Prelims Physics - Work, Energy and Power Question 37 English
The work done on the particle during its displacement of 12 m is
  1. A
    18 J
  2. B
    21 J
  3. C
    26 J
  4. D
    13 J
View written solutionFree

Correct answer: D

AIPMT 2011 Prelims Physics - Work, Energy and Power Question 37 English Explanation

Work done = Area under (F-d) graph

= Area of rectangle ABCD + Area of triangle DCE

= 2×(7−3)+12×2×(12−7)=8+5=13J2 \times \left( {7 - 3} \right) + {1 \over 2} \times 2 \times \left( {12 - 7} \right) = 8 + 5 = 13J2×(7−3)+21​×2×(12−7)=8+5=13J

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