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Work Energy and Power question

2010 · Q98
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Work Energy and Power question

2010 · Q98

NEETPhysicsWork Energy and PowerMCQ+4 / −1
A particle of mass M, starting from rest, undergoes uniform acceleration. If the speed acquired in time T is V, the power delivered to the particle is
  1. A
    MV2T{{M{V^2}} \over T}TMV2​
  2. B
    12MV2T2{1 \over 2}{{M{V^2}} \over {{T^2}}}21​T2MV2​
  3. C
    MV2T2{{M{V^2}} \over {{T^2}}}T2MV2​
  4. D
    12MV2T{1 \over 2}{{M{V^2}} \over T}21​TMV2​
View written solutionFree

Correct answer: D

Power delivered in time T is
P = F·V = MaV

or P=MVdVdT⇒PdT=MVdVP = MV{{dV} \over {dT}} \Rightarrow PdT = MVdVP=MVdTdV​⇒PdT=MVdV

⇒PT=MV22 \Rightarrow PT = {{M{V^2}} \over 2}⇒PT=2MV2​ or P=12MV2TP = {1 \over 2}{{M{V^2}} \over T}P=21​TMV2​

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