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Work Energy and Power question

2006 · Q158
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Work Energy and Power question

2006 · Q158

NEETPhysicsWork Energy and PowerMCQ+4 / −1
300 J of work is done in sliding a 2 kg block up an inclined plane of height 10 m. Work done against friction is (Take g = 10 m/s2)
  1. A
    1000 J
  2. B
    200 J
  3. C
    100 J
  4. D
    zero
View written solutionFree

Correct answer: C

Loss in potential energy = mgh

= 2 × 10 × 10 = 200 J.

Gain in kinetic energy = work done = 300 J

∴\therefore∴ Work done against friction = 300 – 200 = 100 J

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