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Waves question

2002 · Q170
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Waves question

2002 · Q170

NEETPhysicsWavesMCQ+4 / −1
A wave travelling in positive X-direction with a === 0.2 ms−-−2, velocity = 360 ms−-−1 and λ\lambdaλ === 60 m, then correct expression for the wave is
  1. A
    y=0.2sin⁡[2π(6t+x60)]y = 0.2\sin \left[ {2\pi \left( {6t + {x \over {60}}} \right)} \right]y=0.2sin[2π(6t+60x​)]
  2. B
    y=0.2sin⁡[π(6t+x60)]y = 0.2\sin \left[ {\pi \left( {6t + {x \over {60}}} \right)} \right]y=0.2sin[π(6t+60x​)]
  3. C
    y=0.2sin⁡[2π(6t−x60)]y = 0.2\sin \left[ {2\pi \left( {6t - {x \over {60}}} \right)} \right]y=0.2sin[2π(6t−60x​)]
  4. D
    y=0.2sin⁡[π(6t−x60)]y = 0.2\sin \left[ {\pi \left( {6t - {x \over {60}}} \right)} \right]y=0.2sin[π(6t−60x​)]
View written solutionFree

Correct answer: C

The equation of progressive wave travelling in positive x-direction is given by

y=asin⁡2πλ(vt−x)y = a\sin {{2\pi } \over \lambda }\left( {vt - x} \right)y=asinλ2π​(vt−x)

Here a = 0.2 m, v = 360 m/sec, λ\lambda λ = 60 m

∴y=0.2sin⁡2π60(360t−x) \therefore y = 0.2\sin {{2\pi } \over {60}}\left( {360t - x} \right)∴y=0.2sin602π​(360t−x)

=0.2sin[2π(6t−x60)] = 0.2sin\left[ {2\pi \left( {6t - {x \over {60}}} \right)} \right]=0.2sin[2π(6t−60x​)]

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