NEETPhysicsWavesMCQ+4 / −1
The overtone of a closed organ pipe is same as that of overtone of an open pipe. The ratio of the length of the closed pipe to the length of the open pipe is :
- A8 : 9
- B9 : 7
- C9 : 8
- D7 : 9
View written solutionFree
Correct answer: C
$$\begin{aligned} & \mathrm{n}_{\text {oop }}=(2 \mathrm{M}+1)^{\text {th }} \text { Har. }=(2 \times 4+1) \times \frac{\mathrm{V}}{4 \ell_{\mathrm{c}}}=\frac{9 \mathrm{~V}}{4 \ell_{\mathrm{c}}} \\ & \mathrm{n}_{\text {oop }}=(\mathrm{M}+1)^{\text {th }} \text { Har. }=(3+1) \frac{\mathrm{V}}{2 \ell_0}=\frac{4 \mathrm{~V}}{2 \ell_0} \\ & \text { now } \frac{9 \mathrm{~V}}{4 \ell_{\mathrm{c}}}=\frac{4 \mathrm{~V}}{2 \ell_0} \\ & \frac{\ell_{\mathrm{c}}}{\ell_0}=\frac{18}{16}=\frac{9}{8} \end{aligned} $$
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