NEETPhysicsWavesMCQ+4 / −1
A pipe open at both ends has a fundamental frequency in air. The pipe is now dipped vertically in a water drum to half of its length. The fundamental frequency of the air column is now equal to:
- A
- B
- C
- D
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Correct answer: D
Fundamental frequency of open pipe (at both ends) $f=\frac{V}{2 L} \ldots$ (i)

Now immersed in water open pipe behaves as closed pipe.

$$\begin{aligned} \& f^{\prime}=\frac{v}{4\left(\frac{L}{2}\right)}=\frac{v}{2 L} \quad\text{..... (ii)}\\ \& f=f^{\prime} \end{aligned}$$
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