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Units and Measurement question

2004 · Q160
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Units and Measurement question

2004 · Q160

NEETPhysicsUnits and MeasurementMCQ+4 / −1
The dimensions of universal gravitational constant are
  1. A
    [M−-−1L3T−-−2]
  2. B
    [ML2T−-−1]
  3. C
    [M−-−2L3T−-−2]
  4. D
    [M−-−2L2T−-−1]
View written solutionFree

Correct answer: A

F = Gm1m2r2{{G{m_1}{m_2}} \over {{r^2}}}r2Gm1​m2​​

⇒\Rightarrow⇒ G = F×r2m1m2{{F \times {r^2}} \over {{m_1}{m_2}}}m1​m2​F×r2​

∴\therefore∴ Dimension of G = [MLT−2][L2][M][M]{{\left[ {ML{T^{ - 2}}} \right]\left[ {{L^2}} \right]} \over {\left[ M \right]\left[ M \right]}}[M][M][MLT−2][L2]​ = [M−1L3T−2]\left[ {{M^{ - 1}}{L^3}{T^{ - 2}}} \right][M−1L3T−2]

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