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Units and Measurement question

2024 · Q200
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Units and Measurement question

2024 · Q200

NEETPhysicsUnits and MeasurementMCQ+4 / −1

A force defined by F=αt2+βtF=\alpha t^2+\beta tF=αt2+βt acts on a particle at a given time ttt. The factor which is dimensionless, if α\alphaα and β\betaβ are constants, is:

  1. A
    βt/α\beta t / \alphaβt/α
  2. B
    αt/β\alpha t / \betaαt/β
  3. C
    αβt\alpha \beta tαβt
  4. D
    αβ/t\alpha \beta / tαβ/t
View written solutionFree

Correct answer: B

The force acting on a particle at a given time $ t $ is defined as $ F = \alpha t^2 + \beta t $, where $ \alpha $ and $ \beta $ are constants. We need to determine which factor is dimensionless if $ \alpha $ and $ \beta $ are constants.

Using the principle of homogeneity of dimensions:

$ \begin{aligned} & [F] = [\alpha t^2] = [\beta t] \\ & [\alpha] = \frac{[F]}{[t^2]} \quad \text{and} \quad [\beta] = \frac{[F]}{[t]} \\ & \therefore \quad [\alpha][t] = [\beta] \\ & \therefore \quad \frac{\alpha t}{\beta} = \text{dimensionless} \end{aligned} $

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