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Rotational Motion question

2024 · Q166
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Rotational Motion question

2024 · Q166

NEETPhysicsRotational MotionMCQ+4 / −1

The radius of gyration of a solid sphere of mass 5 kg5 \mathrm{~kg}5 kg about XYX YXY is 5 m5 \mathrm{~m}5 m as shown in figure. The radius of the sphere is 5x7 m\frac{5 x}{\sqrt{7}} \mathrm{~m}7​5x​ m, then the value of xxx is:

NEET 2024 (Re-Examination) Physics - Rotational Motion Question 4 English

  1. A
    5
  2. B
    2\sqrt22​
  3. C
    3\sqrt33​
  4. D
    5\sqrt55​
View written solutionFree

Correct answer: D

$$I_{X Y}=I_{C M}+M R^2=\frac{2}{5} M R^2+M R^2=\frac{7}{5} M R^2=\frac{7}{5} \times 5 R^2=7 R^2\quad \text{.... (1)}$$

$$\begin{aligned} & I_{X Y}=M K^2=5 \times 5^2 \quad \ldots(2) \\ & \therefore 5 \times 5^2=7 \times R^2 \quad \text { [From (1) and (2)] } \\ & \Rightarrow R=\sqrt{\frac{5}{7}} \times 5=\frac{5 x}{\sqrt{7}} \quad \text { (Given) } \\ & \therefore x=\sqrt{5} \end{aligned}$$

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