NEETPhysicsRotational MotionMCQ+4 / −1
The ratio of the radius of gyration of a thin uniform disc about an axis passing through its centre and normal to its plane to the radius of gyration of the disc about its diameter is
- A2 : 1
- B: 1
- C4 : 1
- D1 :
View written solutionFree
Correct answer: B

$${l_1} = {{M{R^2}} \over 2}$$
$${k_1} = \sqrt {{{{l_1}} \over M}} $$
$$ = {R \over {\sqrt 2 }}$$

$${l_2} = {{M{R^2}} \over 4}$$
$${k_2} = \sqrt {{{{l_2}} \over M}} $$
$ = {R \over 2}$
$${{{k_1}} \over {{k_2}}} = {{{R \over {\sqrt 2 }}} \over {{R \over 2}}}$$
$ = \sqrt 2 :1$
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