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Rotational Motion question

2023 · Q169
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Rotational Motion question

2023 · Q169

NEETPhysicsRotational MotionMCQ+4 / −1

A constant torque of 100 N m100 \mathrm{~N} \mathrm{~m}100 N m turns a wheel of moment of inertia 300 kg m2300 \mathrm{~kg} \mathrm{~m}^2300 kg m2 about an axis passing through its centre. Starting from rest, its angular velocity after 3 s3 \mathrm{~s}3 s is :-

  1. A
    1 rad/s
  2. B
    5 rad/s
  3. C
    10 rad/s
  4. D
    15 rad/s
View written solutionFree

Correct answer: A

$$\begin{aligned} \tau & =\mathrm{I} \alpha \Rightarrow \alpha=\frac{\tau}{\mathrm{I}}=\frac{100}{300}=\frac{1}{3} ~\mathrm{rad} / \mathrm{sec}^2 \\ \omega_{\mathrm{i}} & =0 \\ \omega_{\mathrm{f}} & =\omega_{\mathrm{i}}+\alpha \mathrm{t} \\ & =0+\frac{1}{3} \times 3 \\ \omega_{\mathrm{f}} & =1 ~\mathrm{rad} / \mathrm{sec}\end{aligned}$$

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