NEETPhysicsRotational MotionMCQ+4 / −1
A constant torque of turns a wheel of moment of inertia about an axis passing through its centre. Starting from rest, its angular velocity after is :-
- A1 rad/s
- B5 rad/s
- C10 rad/s
- D15 rad/s
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Correct answer: A
$$\begin{aligned} \tau & =\mathrm{I} \alpha \Rightarrow \alpha=\frac{\tau}{\mathrm{I}}=\frac{100}{300}=\frac{1}{3} ~\mathrm{rad} / \mathrm{sec}^2 \\ \omega_{\mathrm{i}} & =0 \\ \omega_{\mathrm{f}} & =\omega_{\mathrm{i}}+\alpha \mathrm{t} \\ & =0+\frac{1}{3} \times 3 \\ \omega_{\mathrm{f}} & =1 ~\mathrm{rad} / \mathrm{sec}\end{aligned}$$
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