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Rotational Motion question

2019 · Q126
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Rotational Motion question

2019 · Q126

NEETPhysicsRotational MotionMCQ+4 / −1
Two particles A and B are moving in uniform circular motion in concentric circles of radii rA and rB with speed vA and vB respecitively. Their time period of rotation is the same. The ratio of angular speed of A to that of B will be :
  1. A
    vA : vB
  2. B
    1 : 1
  3. C
    rB : rA
  4. D
    rA : rB
View written solutionFree

Correct answer: B

Since, the time period for both the particle in same So, TA = TB = T

Angular velocity for A, (ωA{\omega _A}ωA​) = 2πTA{{2\pi } \over {{T_A}}}TA​2π​

Angular velocity for B, (ωB{\omega _B}ωB​) = 2πTB{{2\pi } \over {{T_B}}}TB​2π​

Now, the required ratio is

ωAωB=TBTA=TT=1{{{\omega _A}} \over {{\omega _B}}} = {{{T_B}} \over {{T_A}}} = {T \over T} = 1ωB​ωA​​=TA​TB​​=TT​=1

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