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Rotational Motion question

2008 · Q156
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Rotational Motion question

2008 · Q156

NEETPhysicsRotational MotionMCQ+4 / −1
A thin rod of length L and mass M is bent at its midpoint into two halves so that the angle between them is 90o. The moment of inertia of the bent rod about an axis passing through the bending point and perpendicular to the plane defined by the two halves of the rod is
  1. A
    ML26{{M{L^2}} \over 6}6ML2​
  2. B
    2ML224{{\sqrt 2 M{L^2}} \over {24}}242​ML2​
  3. C
    ML224{{M{L^2}} \over {24}}24ML2​
  4. D
    ML212{{M{L^2}} \over {12}}12ML2​
View written solutionFree

Correct answer: D

Total mass = M, total length = L
Moment of inertia of OA about O = Moment of inertia of OB about O.

⇒\Rightarrow⇒ M.I total = 2×(M2)(L2)2.13=ML2122 \times \left( {{M \over 2}} \right){\left( {{L \over 2}} \right)^2}.{1 \over 3} = {{M{L^2}} \over {12}}2×(2M​)(2L​)2.31​=12ML2​

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