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Rotational Motion question

2005 · Q162
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Rotational Motion question

2005 · Q162

NEETPhysicsRotational MotionMCQ+4 / −1
The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is
  1. A
    MR2
  2. B
    12{1 \over 2}21​ MR2
  3. C
    32{3 \over 2}23​ MR2
  4. D
    72{7 \over 2}27​ MR2
View written solutionFree

Correct answer: C

Moment of Inertia of uniform circular disc with radius ‘R’ and mass ‘M’ about axis passing through C.M. and normal to disc will be :

ICM = (1/2) MR2

Moment of Inertia about axis tangential to disc :

IT = ICM + MR2

IT = (1/2) MR2

  • MR2

    = (3/2) MR2
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