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Rotational Motion question

2006 · Q162
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Rotational Motion question

2006 · Q162

NEETPhysicsRotational MotionMCQ+4 / −1
The moment of inertia of a uniform circular disc of radius R and mass M about an axis touching the disc at its diameter and normal to the disc
  1. A
    12{1 \over 2}21​MR2
  2. B
    MR2
  3. C
    25MR2{2 \over 5}M{R^2}52​MR2
  4. D
    32MR2{3 \over 2}M{R^2}23​MR2
View written solutionFree

Correct answer: D

Moment of inertia of a uniform circular disc about an axis through its centre and perpendicular to its plane is IC=12MR2{I_C} = {1 \over 2}M{R^2}IC​=21​MR2 by the theorem of parallel axes.

∴\therefore∴ Moment of inertia of a uniform circular disc about an axis touching the disc at its diameter and normal to the disc is I.

I=IC+Mh2=12MR2+MR2=32MR2I = {I_C} + M{h^2} = {1 \over 2}M{R^2} + M{R^2} = {3 \over 2}M{R^2}I=IC​+Mh2=21​MR2+MR2=23​MR2

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