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Properties of Matter question

2016 · Q152
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Properties of Matter question

2016 · Q152

NEETPhysicsProperties of MatterMCQ+4 / −1
Two identical bodies are made of a material for which the heat capacity increases with temperature. One of these is at 100oC, while the other one is at 0oC. If the two bodies are brought into contact, then, assuming no heat loss, the final common temperature is
  1. A
    50 oC
  2. B
    more than 50 oC
  3. C
    less than 50 oC but greater than 0 oC
  4. D
    0 oC
View written solutionFree

Correct answer: B

If the final common temperature is Tc, Cc and Ch average heat capacities of cold and hot bodies then as per principle of calorimetry,

heat lost = heat gained

Ch (100°C – Tc) = Cc × Tc

Now Tc = Ch/(Ch + Cc) × 100°C

= 100/[1 + (Cc/Ch)],     where Cc/Ch < 1

It is seen that 1 + Cc/Ch < 2

Hence, Tc > (100/2)°C or Tc > 50°C

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