NEETPhysicsProperties of MatterMCQ+4 / −1
A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof is 250 m2. Assuming that the pressure inside the house is atmospheric pressure, the force exerted by the wind on the roof and the direction of the force will be
- A2.4 105 N, upwards
- B2.4 105 N, downwards
- C4.8 105 N, downwards
- D4.8 105 N, upwards
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Correct answer: A
Using Bernoulli's theorem and assuming density constant,
P1+1/2ρv12 = P2+1/2ρv22
where:
P2 = pressure outside house
P1 = pressure inside house
v1 = speed of air inside house
v2 = speed of air outside house
Pressure difference,
P1 – P2 = 1/2ρ [v22 – v12]
Now, P1 – P2 = 1/2 × 1.2 [402 – 02]
P1 – P2 = 960 N/m2
Since Pressure P = Force/Area, so force acting on roof will be :
F = P × A
F = 960 × 250
F = 960 × 1000/4
F = 24×104 or 2.4×105 N
which is acting upward.
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