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Properties of Matter question

2014 · Q152
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Properties of Matter question

2014 · Q152

NEETPhysicsProperties of MatterMCQ+4 / −1
Steam at 100oC is passed into 20 g of water at 10oC. When water acquires a temperature of 80oC, the mass of water present will be
[Take specific heat of water = 1 cal g−-−1 oC−-−1 and latent heat of steam = 540 cal g−-−1]
  1. A
    24 g
  2. B
    31.5 g
  3. C
    42.5 g
  4. D
    22.5 g
View written solutionFree

Correct answer: D

According to the principle of calorimetry.

Heat lost = Heat gained

mLv+mswΔθ=mwswΔθm{L_v} + m{s_w}\Delta \theta = {m_w}{s_w}\Delta \theta mLv​+msw​Δθ=mw​sw​Δθ

⇒\Rightarrow⇒ m × 540 + m × 1 × (100 – 80)

= 20 × 1 × (80 – 10)

⇒\Rightarrow⇒ m = 2.5 g

Therefore total mass of water at 80°C

= (20 + 2.5) g = 22.5 g

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