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Oscillations question

2010 · Q182
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Oscillations question

2010 · Q182

NEETPhysicsOscillationsMCQ+4 / −1
The period of oscillation of a mass M suspended from a strong of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
  1. A
    T
  2. B
    T2{T \over {\sqrt 2 }}2​T​
  3. C
    2T
  4. D
    2T\sqrt 2 T2​T
View written solutionFree

Correct answer: D

T=2πmKT = 2\pi \sqrt {{m \over K}} T=2πKm​​

∴T1T2=M1M2\therefore {{{T_1}} \over {{T_2}}} = \sqrt {{{{M_1}} \over {{M_2}}}}∴T2​T1​​=M2​M1​​​

∴\therefore∴ T2=T1M2M1=T12MM{T_2} = {T_1}\sqrt {{{{M_2}} \over {{M_1}}}} = {T_1}\sqrt {{{2M} \over M}} T2​=T1​M1​M2​​​=T1​M2M​​

T2=T12=2T{T_2} = {T_1}\sqrt 2 = \sqrt 2 TT2​=T1​2​=2​T     (where T1 =T)

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