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Motion in A Straight Line question

2019 · Q150
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Motion in A Straight Line question

2019 · Q150

NEETPhysicsMotion in A Straight LineMCQ+4 / −1
The speed of a swimmer in still water is 20 m/s. The speed of river water is 10 m/s and is flowing due east. If he is standing on the south bank and wishes to cross the river along the shortest path, the angle at which he should make his strokes w.r.t. north is given by :
  1. A
    0o
  2. B
    60
  3. C
    45o west
  4. D
    30o west
View written solutionFree

Correct answer: D

NEET 2019 Physics - Motion in a Straight Line Question 12 English Explanation


VSR = 20 m/s

VRG = 10 m/s

$${\overrightarrow V _{SG}} = {\overrightarrow V _{SR}} + {\overrightarrow V _{RG}}$$

sin $\theta $ = $$\left| {{{{{\overrightarrow V }_{RG}}} \over {{{\overrightarrow V }_{SR}}}}} \right|$$ = ${{10} \over {20}}$ = ${1 \over 2}$

$ \Rightarrow $ θ = 30° west-side
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