NEETPhysicsMotion in A PlaneMCQ+4 / −1
Let and be the angular speed of the second hand, minute hand and hour hand of a smoothly running analog clock, respectively. If and are their respective angular distances in 1 minute then the factor which remains constant is
- A
- B
- C
- D
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Correct answer: A
$$\begin{aligned} & \omega_1=\frac{2 \pi}{60} ; \quad x_1=\frac{2 \pi}{60} \times 60=2 \pi \\\\ & \omega_2=\frac{2 \pi}{3600} ; \quad x_2=\frac{2 \pi}{3600} \times 60=\frac{2 \pi}{60} \\\\ & \omega_3=\frac{2 \pi}{3600 \times 12} ; \quad x_3=\frac{2 \pi}{3600 \times 12} \times 60=\frac{2 \pi}{720} \\\\ & \frac{\omega_1}{x_1}=\frac{\omega_2}{x_2}=\frac{\omega_3}{x_3}=\frac{1}{60}=k \end{aligned}$$
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