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Magnetism and Matter question

2024 · Q155
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Magnetism and Matter question

2024 · Q155

NEETPhysicsMagnetism and MatterMCQ+4 / −1

In a uniform magnetic field of 0.049 T0.049 \mathrm{~T}0.049 T, a magnetic needle performs 20 complete oscillations in 5 seconds as shown. The moment of inertia of the needle is 9.8×10−6 kg m29.8 \times 10^{-6} \mathrm{~kg} \mathrm{~m}^29.8×10−6 kg m2. If the magnitude of magnetic moment of the needle is x×10−5 Am2x \times 10^{-5} \mathrm{~Am}^2x×10−5 Am2, then the value of 'xxx' is :

NEET 2024 Physics - Magnetism and Matter Question 7 English

  1. A
    5π2\pi^2π2
  2. B
    128π2\pi^2π2
  3. C
    50π2\pi^2π2
  4. D
    1280π2\pi^2π2
View written solutionFree

Correct answer: D

Time period of Oscillation, $$T=2 \pi \sqrt{\frac{I}{M B}}$$

$$\begin{aligned} & \Rightarrow \frac{1}{4}=2 \pi \sqrt{\frac{9.8 \times 10^{-6}}{M \times 0.049}} \\ & \Rightarrow \quad \frac{1}{16}=4 \pi^2 \times \frac{9.8 \times 10^{-6}}{M \times 49 \times 10^{-3}} \\ & \Rightarrow \quad M=\frac{4 \pi^2 \times 9.8 \times 10^{-6}}{49 \times 10^{-3}} \times 16 \\ & \quad=\frac{4 \pi^2 \times 9.8 \times 16 \times 10^{-3}}{49} \\ & \quad=12.8 \pi^2 \times 10^{-3} \times 10^{-2} \times 10^2 \\ & =1280 \pi^2 \times 10^{-5} \mathrm{Am}^2 \end{aligned}$$

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