In a uniform magnetic field of , a magnetic needle performs 20 complete oscillations in 5 seconds as shown. The moment of inertia of the needle is . If the magnitude of magnetic moment of the needle is , then the value of '' is :

- A5
- B128
- C50
- D1280
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Correct answer: D
Time period of Oscillation, $$T=2 \pi \sqrt{\frac{I}{M B}}$$
$$\begin{aligned} & \Rightarrow \frac{1}{4}=2 \pi \sqrt{\frac{9.8 \times 10^{-6}}{M \times 0.049}} \\ & \Rightarrow \quad \frac{1}{16}=4 \pi^2 \times \frac{9.8 \times 10^{-6}}{M \times 49 \times 10^{-3}} \\ & \Rightarrow \quad M=\frac{4 \pi^2 \times 9.8 \times 10^{-6}}{49 \times 10^{-3}} \times 16 \\ & \quad=\frac{4 \pi^2 \times 9.8 \times 16 \times 10^{-3}}{49} \\ & \quad=12.8 \pi^2 \times 10^{-3} \times 10^{-2} \times 10^2 \\ & =1280 \pi^2 \times 10^{-5} \mathrm{Am}^2 \end{aligned}$$
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