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Magnetism and Matter question

2021 · Q165
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Magnetism and Matter question

2021 · Q165

NEETPhysicsMagnetism and MatterMCQ+4 / −1
A uniform conducting wire of length 12a and resistance 'R' is wound up as a current carrying coil in the shape of ,

(i) an equilateral tringle of side 'a'

(ii) A square of side 'a'

The magnetic dipole moments of the coil in each case respectively are :
  1. A
    4Ia2 and 3Ia2
  2. B
    3\sqrt 33​ Ia2 and 3I a2
  3. C
    3Ia2 and Ia2
  4. D
    3Ia2 and 4Ia2
View written solutionFree

Correct answer: B

NEET 2021 Physics - Magnetism and Matter Question 12 English Explanation 1


x=a2−a24=3a24=3a24=32ax = \sqrt {{a^2} - {{{a^2}} \over 4}} = \sqrt {{{3{a^2}} \over 4}} = \sqrt {{{3{a^2}} \over 4}} = {{\sqrt 3 } \over 2}ax=a2−4a2​​=43a2​​=43a2​​=23​​a

A1=12×a×32a{A_1} = {1 \over 2} \times a \times {{\sqrt 3 } \over 2}aA1​=21​×a×23​​a

A1=34a2{A_1} = {{\sqrt 3 } \over 4}{a^2}A1​=43​​a2

μ1=N1IA1{\mu _1} = {N_1}I{A_1}μ1​=N1​IA1​

μ1=4I34a2{\mu _1} = {{4I\sqrt 3 } \over 4}{a^2}μ1​=44I3​​a2

μ1=3Ia2{\mu _1} = \sqrt 3 I{a^2}μ1​=3​Ia2

NEET 2021 Physics - Magnetism and Matter Question 12 English Explanation 2


A2=a2{A_2} = {a^2}A2​=a2

μ2=N2IA2{\mu _2} = {N_2}I{A_2}μ2​=N2​IA2​

=3×I×a2 = 3 \times I \times {a^2}=3×I×a2

μ2=3Ia2{\mu _2} = 3I{a^2}μ2​=3Ia2

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