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Magnetism and Matter question

2017 · Q130
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Magnetism and Matter question

2017 · Q130

NEETPhysicsMagnetism and MatterMCQ+4 / −1
A 250-turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85 μ\muμA and subjected to a magnetic field of strength 0.85 T. Work done for rotating the coil by 180o against the torque is
  1. A
    4.55 μ\muμJ
  2. B
    2.3 μ\muμJ
  3. C
    1.15 μ\muμJ
  4. D
    9.1 μ\muμJ
View written solutionFree

Correct answer: D

Given: n = 250, l = 2.1 cm, W = 1.25 cm, i = 85 μA, B = 0.85 T

Now W = MB (cos θ1 – cos θ2) = 2MB = 2(iNA)B

= 2 × 85 × 10–6 × 250 × 2.1 × 1.25 × 10–4 × 0.85

= 9.1 × 10–6 J

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