NEETPhysicsMagnetism and MatterMCQ+4 / −1
A rectangular coil of length 0.12 m and width 0.1 m having 50 turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 weber/m2. The coil carries a current of 2 A. If the plane of the coil is inclined at an angle of 30o with the direction of the field, the torque required to keep the coil in stable equilibrium will be
- A0.24 Nm
- B0.12 Nm
- C0.15 Nm
- D0.20 Nm
View written solutionFree
Correct answer: D

The required torque is $\tau $ = NIABsin$\theta $
= (50)(2 A)(0.012 m2)(0.2 Wb/m2) sin60°
= 0.20 N m
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