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Magnetism and Matter question

2011 · Q92
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Magnetism and Matter question

2011 · Q92

NEETPhysicsMagnetism and MatterMCQ+4 / −1
A short bar magnet of magnetic moment 0.4 J T−-−1 is placed in a uniform magnetic field of 0.16 T. The magnet is in stable equilibrium when the potential energy is
  1. A
    0.064 J
  2. B
    −-− 0.064 J
  3. C
    zero
  4. D
    −-− 0.082 J
View written solutionFree

Correct answer: B

When a bar magnet of magnetic moment is placed in a uniform magnetic field , its potential energy is

U = −M→.B→=MBcos⁡θ- \overrightarrow M .\overrightarrow B = MB\cos \theta−M.B=MBcosθ

For stable equilibrium, θ\theta θ = 0o

U = –MB = – (0.4) (0.16) = – 0.064 J

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