NEETPhysicsLaws of MotionMCQ+4 / −1
In the diagram shown, the normal reaction force between 2 kg and 1 kg is (Consider the surface, to be smooth) :
(Given g = 10 ms2)
- A10 N
- B25 N
- C39 N
- D6 N
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Correct answer: B
Assuming all three blocks as system
Hence, acceleration of system
$$a = {{60 - 30 - 18} \over 6} = {{12} \over 6} = 2$$ m/s2
$a = 2$ m/s2, upward along the incline.
Now, for 1 kg block
$$ \Rightarrow {N_{12}} - 18 - 5 = 1 \times 2$$
$$ \Rightarrow {N_{12}} - 23 = 2$$
$$ \Rightarrow {N_{12}} = 25$$ N
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