NEETPhysicsLaws of MotionMCQ+4 / −1
A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is
- AMV
- B1.5 MV
- C2MV
- Dzero
View written solutionFree
Correct answer: C
Impulse experienced by the body = change in momentum
= MV – (–MV)
= 2MV.
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