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Laws of Motion question

2009 · Q156
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Laws of Motion question

2009 · Q156

NEETPhysicsLaws of MotionMCQ+4 / −1
A body, under the action of a force F→=6i^−8j^+10k^,\overrightarrow F = 6\widehat i - 8\widehat j + 10\widehat k,F=6i−8j​+10k, acquires an accelerations of 1 m/s2. The mass of this body must be
  1. A
    10 kg
  2. B
    20 kg
  3. C
    102\sqrt 22​ kg
  4. D
    210\sqrt {10}10​ kg
View written solutionFree

Correct answer: C

F→=6i^−8j^+10k^\overrightarrow F = 6\widehat i - 8\widehat j + 10\widehat kF=6i−8j​+10k

∣F→∣=36+64+100\left| {\overrightarrow F } \right| = \sqrt {36 + 64 + 100} ​F​=36+64+100​

=200N=102N = \sqrt {200} N = 10\sqrt 2 N=200​N=102​N

Acceleration, a = 1 m s–2

∴\therefore∴ Mass, M=1021=102 kgMass,\,M = {{10\sqrt 2 } \over 1} = 10\sqrt 2 \,kgMass,M=1102​​=102​kg

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