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Laws of Motion question

2008 · Q153
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Laws of Motion question

2008 · Q153

NEETPhysicsLaws of MotionMCQ+4 / −1
AIPMT 2008 Physics - Laws of Motion Question 20 English

Three forces acting on a body are shown in the figure. To have the resultant force only along the y-direction, the magnitude of the minimum additional force needed is
  1. A
    34N{{\sqrt 3 } \over 4}N43​​N
  2. B
    3{\sqrt 3 }3​ N
  3. C
    0.5 N
  4. D
    1.5 N
View written solutionFree

Correct answer: C

The components of 1N and 2N forces along + x axis = 1 cos 60° + 2 sin 30°

=1×12+2×12=12+1=32=1.5N = 1 \times {1 \over 2} + 2 \times {1 \over 2} = {1 \over 2} + 1 = {3 \over 2} = 1.5N=1×21​+2×21​=21​+1=23​=1.5N

AIPMT 2008 Physics - Laws of Motion Question 20 English Explanation


The component of 4 N force along – x-axis

=4sin⁡30o=4×12=2N = 4\sin {30^o} = 4 \times {1 \over 2} = 2N=4sin30o=4×21​=2N

Therefore, if a force of 0.5N is applied along + x-axis, the resultant force along x-axis will become zero and the resultant force will be obtained only along y-axis.

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